220 câu trắc nghiệm tổng hợp Toán cao cấp A2 có đáp án - Phần 4

$${\mathrm{x}}_1=-1-8{\mathrm{x}}_4,{\mathrm{x}}_3=0,{\mathrm{x}}_2=1+2{\mathrm{x}}_4$$

$${\mathrm{x}}_1=-1-8{\mathrm{x}}_4,{\mathrm{x}}_3=1,{\mathrm{x}}_2=1+2{\mathrm{x}}_4$$

$${\mathrm{x}}_1=-1-8{\mathrm{x}}_1,{\mathrm{x}}_3=1,{\mathrm{x}}_2=1+2{\mathrm{x}}_1$$

$${\mathrm{x}}_1=-1-8{\mathrm{x}}_1+2{\mathrm{x}}_2,{\mathrm{x}}_4=1+2{\mathrm{x}}_1-5{\mathrm{x}}_2$$

$$x_1=1,x_2=3-2x_4,x_3=4-2x_4$$

$$x_1=0,x_2=4-2x_4,x_3=3-2x_4$$

$$x_1=1,x_2=3-2x_3,x_3=4+2x_3$$

$$x_1=3+5x_4,x_2=4,x_3=3-x_4$$

$$x_1=2,x_2=3,x_3=-1,x_4=-2$$ là một nghiệm của hệ

$$x_1=\frac{1}{7},x_2=\frac{15}{7},x_3=0,x_4=\frac{-6}{7}$$ là một nghiệm của hệ

$$x_1=-11,x_2=-3,x_3=6,x_4=6$$ là một nghiệm của hệ

Các trường hợp trên đều là nghiệm của hệ

$${\mathrm{x}}_1=2+{\mathrm{x}}_3+7{\mathrm{x}}_4,\mathrm{x}2=-1+5{\mathrm{x}}_3-{\mathrm{x}}_4$$

$${\mathrm{x}}_1=6-26{\mathrm{x}}_3+17{\mathrm{x}}_4,\mathrm{x}2=-1+7{\mathrm{x}}_3-5{\mathrm{x}}_4$$

$${\mathrm{x}}_1=2+6{\mathrm{x}}_3-7{\mathrm{x}}_4,\mathrm{x}2=-1+4{\mathrm{x}}_3-2{\mathrm{x}}_4$$

$${\mathrm{x}}_1=4+11{\mathrm{x}}_4,\mathrm{x}2=-1-6{\mathrm{x}}_4,{\mathrm{x}}_3=2$$

$$x_1=2+2x_4,x_2=3-2x_4,x_3=4-2x_4$$

$$x_1=0,x_2=1+7x_4,x_3=-2-5x_4$$

$$x_1=-4,x_2=-6+3x_3,x_4=7-9x_3$$

Hệ vô nghiệm

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))=2{\mathrm{x}}_1{\mathrm{x}}_2+13{\mathrm{x}}_1{\mathrm{y}}_2-5{\mathrm{y}}_1{\mathrm{y}}_2$$

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))=3{\mathrm{x}}_1{\mathrm{x}}_2+{\mathrm{x}}_1{\mathrm{y}}_2+2{\mathrm{x}}_2{\mathrm{y}}_1+3{\mathrm{y}}_1{\mathrm{y}}_2$$

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))=2{\mathrm{x}}_1{\mathrm{x}}_2-4{\mathrm{x}}_1{\mathrm{y}}_2+4{\mathrm{x}}_2{\mathrm{y}}_1-2{\mathrm{y}}_1{\mathrm{y}}_2$$

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))={\mathrm{x}}_1{\mathrm{y}}_2+{\mathrm{x}}_2{\mathrm{y}}_1-3{\mathrm{y}}_1{\mathrm{y}}_2$$

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))=2{\mathrm{x}}_1{\mathrm{x}}_2+8{\mathrm{x}}_1{\mathrm{y}}_2-{\mathrm{y}}_1{\mathrm{y}}_2$$

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))=3{\mathrm{x}}_1{\mathrm{x}}_2+8{\mathrm{x}}_1{\mathrm{y}}_2+2{\mathrm{x}}_1{\mathrm{y}}_2+{\mathrm{y}}_1{\mathrm{y}}_2$$

$$\eta (({\mathrm{x}}_1,{\mathrm{y}}_1),({\mathrm{x}}_2,{\mathrm{y}}_2))=2{\mathrm{x}}_1{\mathrm{x}}_2+{\mathrm{x}}_1{\mathrm{y}}_2-3{\mathrm{x}}_2{\mathrm{y}}_1+{\mathrm{y}}_1{\mathrm{y}}_2$$

$$-\frac{1}{6}\cos 3\mathrm{x}+\frac{1}{2}\cos \mathrm{x}+\mathrm{C}$$

$$\frac{2}{3}{\cos }^3\mathrm{x}+\mathrm{cosx}+\mathrm{C}$$

$$-\frac{2}{3}{\sin }^3\mathrm{x}+\mathrm{sinx}+\mathrm{C}$$

Đáp án A và C đều đúng

$$\frac{1}{4028}(1+2{\mathrm{x})}^{2013}+\mathrm{C}$$

$$\frac{1}{2}(1+2{\mathrm{x})}^{2013}+\mathrm{C}$$

$$\frac{1}{4024}(1+2{\mathrm{x})}^{2013}+\mathrm{C}$$

$$\frac{1}{2013}(1+2{\mathrm{x})}^{2013}+\mathrm{C}$$

$$\frac{1}{2}\cos \left(\frac{\pi }{3}-\frac{\mathrm{x}}{2}\right)+\mathrm{C}$$

$$4\cos \left(\frac{\pi }{3}-\frac{\mathrm{x}}{4}\right)+\mathrm{C}$$

$$2\sin \left(\frac{\pi }{3}-\frac{\mathrm{x}}{2}\right)+\mathrm{C}$$

$$\frac{1}{2}\sin \left(\frac{\pi }{3}-\frac{\mathrm{x}}{2}\right)+\mathrm{C}$$

$$-\frac{1}{3}\ln |\cos 3x|+\mathrm{C}$$

$$\frac{1}{3}\ln |\cos 5x|+\mathrm{C}$$

$$-\frac{1}{3}\ln |\sin 3x|+\mathrm{C}$$

$$\frac{1}{5}\ln |\sin 5x|+\mathrm{C}$$

$$\ln |\mathrm{x}-2|-\ln |\mathrm{x}-4|+\mathrm{C}$$

$$\ln |\mathrm{x}-5|-\ln |\mathrm{x}-2|+\mathrm{C}$$

$$\frac{\ln |\mathrm{x}-5|}{\ln |\mathrm{x}-2|}+\mathrm{C}$$

$$\ln |(\mathrm{x}-4)(2-2)|+\mathrm{C}$$

$$\frac{{\ln }^3\mathrm{x}-2\ln \mathrm{x}+1}{{\mathrm{x}}^2}+\mathrm{C}$$

$$(\ln \mathrm{x}-1{)}^7+\mathrm{C}$$

$${\ln }^3\mathrm{x}-2\ln \mathrm{x}+1+\mathrm{C}]$$

$$\frac{3}{5}\sqrt[3]{5x+3}+\mathrm{C}$$

$$-\frac{3}{2}\sqrt[3]{2x+3}+\mathrm{C}$$

$$\sqrt[3]{2x+3}+\mathrm{C}$$

$$\frac{1}{2}\sqrt[3]{5x+3}+\mathrm{C}$$

$$\frac{1}{3}\cot (-3\mathrm{x}+1)+\mathrm{C}$$

$$\frac{1}{2}\tan (-2\mathrm{x}+1)+\mathrm{C}$$

$$-\frac{1}{3}\cot (-3\mathrm{x}+1)+\mathrm{C}$$

$$-\frac{1}{2}\tan (-2\mathrm{x}+1)+\mathrm{C}$$

$$\frac{2}{{\mathrm{e}}^{\mathrm{x}}-1}+\mathrm{C}$$

$$-\frac{2}{{\mathrm{e}}^{\mathrm{x}}-1}+\mathrm{C}$$

$$-\frac{{({\mathrm{e}}^{\mathrm{x}}-1)}^3}{3}+\mathrm{C}$$

$$\frac{{({\mathrm{e}}^{\mathrm{x}}-1)}^3}{3}+\mathrm{C}$$

$$\frac{\pi }{8}$$

$-\frac{\pi }{8}$

$\frac{\pi }{2}$

1

2

$${\mathrm{e}}^2-1$$

$$2{\mathrm{e}}^1+2$$

e

$$\frac{3\pi }{2}$$

$\frac{\pi }{4}$

1

0

2ln2

2ln3

-1

1