125 câu trắc nghiệm tổng hợp Toán cao cấp A1 có đáp án - Phần 4

f'(0) = 0

f'(0) = -1

f'(0) = 1

Không tồn tại

$${\mathrm{a}}^{\mathrm{n}}.{\mathrm{e}}^{\mathrm{ax}}$$

$${\mathrm{a}}^{\mathrm{n}}-1.{\mathrm{e}}^{\mathrm{ax}}$$

$${\mathrm{a}}^{\mathrm{n}}.{\mathrm{e}}^{\mathrm{x}}$$

Kết quả khác

-1

+∞

0

e-1/2

$$y=x-\frac{1}{4}$$

$$y=\frac{x}{2}-\frac{1}{2}$$

$$y=\frac{x}{2}-\frac{1}{4}$$

$$y=\frac{x}{2}+\frac{1}{4}$$

Đáp án khác

$${{\mathrm{f}}^{\prime }}_{-}(0)=-1$$

$${{\mathrm{f}}^{\prime }}_{-}(0)=0$$

$${{\mathrm{f}}^{\prime }}_{-}(0)=1$$

$$\frac{(\mathrm{n}-1)!}{{\mathrm{x}}^{\mathrm{n}}}$$

Kết quả khác

$$(-1{)}^{\mathrm{n}-1}.\frac{(\mathrm{n}-1)!}{{\mathrm{x}}^{\mathrm{n}}}$$

$${\mathrm{a}}^{\mathrm{n}-1}.{\mathrm{e}}^{\mathrm{ax}}$$

0

-1/80

10

20

2x - 3

0

3 - 2x

2x + 3

0

-1

-2

-1/2

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=-\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=2\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=0$$

r = 1/e

r = 1

r = e

$$+\infty$$

$$\underset{\mathrm{a}}{\overset{\mathrm{c}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}+\underset{\mathrm{c}}{\overset{\mathrm{b}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx};\mathrm{c}\in \mathrm{R}$$

$$\underset{\mathrm{a}}{\overset{\mathrm{c}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}+\underset{\mathrm{c}}{\overset{\mathrm{b}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx};a\le c\le b$$

$$\underset{\mathrm{c}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}+\underset{\mathrm{b}}{\overset{\mathrm{c}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx};a\le c\le b$$

$$\underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{f}(\mathrm{t})\mathrm{dx}$$

$$-\frac{1}{4}\ln 5+\frac{2}{3}\ln 2$$

$$\frac{1}{4}\ln 5+\frac{2}{3}\ln 2$$

$$-\frac{1}{4}\ln 5$$

$$\frac{2}{3}\ln 2$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=2\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=-\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{-\mathrm{a}}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=2\underset{-a/2}{\overset{a/2}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\frac{1}{5}$$

$$\frac{1}{64}$$

$$\frac{1}{8}$$

$\infty$

$$\frac{1}{3}\pi b{a}^2$$

$$\frac{2}{3}\pi b{a}^2$$

$$\frac{4}{3}\pi b{a}^2$$

$$\pi b{a}^2$$

$${\mathrm{u}}_1+{\mathrm{u}}_2+...+{\mathrm{u}}_{\mathrm{n}}+...$$được gọi là một dãy số

$$\sum _{\mathrm{i}=1}^{\mathrm{n}}{\mathrm{u}}_{\mathrm{i}}$$được gọi là một chuỗi số

$${\mathrm{u}}_1+{\mathrm{u}}_2+...+{\mathrm{u}}_{\mathrm{n}}+...$$được gọi là một chuỗi số

$${\mathrm{u}}_1^2{,\mathrm{u}}_2^2,...{\mathrm{u}}_{\mathrm{n}}^2,...$$được gọi là một chuỗi số dương

$$\mathrm{S}=+\infty$$

S = 2

S = 3

S = 0

$\frac{\pi }{2}$

-1

1

0

$$\left(\forall \mathrm{x}\in \left[\mathrm{a},\mathrm{b}\right]\right)\mathrm{f}(\mathrm{x})<\mathrm{g}(\mathrm{x})\Rightarrow \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}>\underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{g}(\mathrm{x})\mathrm{dx}$$>

$$\left(\forall \mathrm{x}\in \left[\mathrm{a},\mathrm{b}\right]\right)\mathrm{f}(\mathrm{x})\le \mathrm{g}(\mathrm{x})\Rightarrow \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}\le \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{g}(\mathrm{x})\mathrm{dx}$$

$$\left(\forall \mathrm{x}\in \left[\mathrm{a},\mathrm{b}\right]\right)\mathrm{f}(\mathrm{x})\le \mathrm{g}(\mathrm{x})\Rightarrow \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{g}(\mathrm{x})\mathrm{dx}\le \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{g}(\mathrm{x})\mathrm{dx}$$

$$\mathrm{f}(\mathrm{x})\le \mathrm{g}(\mathrm{x})\Rightarrow \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{g}(\mathrm{x})\mathrm{dx}\le \underset{\mathrm{a}}{\overset{\mathrm{b}}{\int }}\mathrm{g}(\mathrm{x})\mathrm{dx}$$

$$\underset{\mathrm{a}}{\overset{\mathrm{a}+\mathrm{T}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=-\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{\mathrm{a}}{\overset{\mathrm{a}+\mathrm{T}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=\underset{0}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\underset{\mathrm{a}}{\overset{\mathrm{a}+\mathrm{T}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=0$$

$$\underset{\mathrm{a}}{\overset{\mathrm{a}+\mathrm{T}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}=-\underset{T}{\overset{\mathrm{a}}{\int }}\mathrm{f}(\mathrm{x})\mathrm{dx}$$

$$\frac{2}{3}\ln 2$$

$$\frac{3}{2}\ln 2$$

$$-\frac{2}{3}\ln 2$$

$$ln2$$

0

$$\ln \frac{\sqrt{2}+1}{\sqrt{2}-1}$$

$$\ln \frac{\sqrt{2}+1}{3}$$

$$\ln \frac{\sqrt{2}+1}{3(\sqrt{2}-1)}$$

$$\frac{1}{5}$$

0

$\infty$

$$\frac{1}{10}$$

$$1+ln2$$

$$1-ln2$$

$$\frac{1}{5}\ln 2$$

$$\frac{12}{5}\ln 6$$