Bộ 10 Đề kiểm tra học kì I Chuyên đề toán 11: Kiểm tra 15 phút có đáp án (Đề 2)

$\left[0;2\right]$

$\left[-\sqrt{2}-1;\sqrt{2}-1\right]$

$\left[-2\sqrt{2}+2;2\sqrt{2}+2\right]$

$\left[-\sqrt{2};\sqrt{2}+1\right]$

hàm số không lẻ.

hàm số chẵn.

hàm số không chẵn.

hàm số lẻ.

$S=\left\{\frac{\pi }{12}+k\pi ,\frac{5\pi }{12}+k\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{\frac{\pi }{6}+k2\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{\frac{\pi }{12}+k\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{\frac{\pi }{18}+k\frac{\pi }{2},k\in \mathbb{Z}\right\}$

$x=\pm \frac{\pi }{2}+k2\pi ,k\in \mathbb{Z}$

$x=\frac{\pi }{4}+k\frac{\pi }{2},k\in \mathbb{Z}$

$x=\pm \frac{\pi }{3}+k2\pi ,k\in \mathbb{Z}$

$x=\pm \frac{\pi }{4}+k2\pi ,k\in \mathbb{Z}$

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$2t^2+t=0$

$2+2t^2+t=0$

$-2t^2+t+4=0$

$-2t^2+t+2=0$

$x=\frac{\pi }{2}+k\pi \left(k\in \mathbb{Z}\right)$

$x=\frac{\pi }{3}+k\pi \left(k\in \mathbb{Z}\right)$

$x=\frac{\pi }{3}+k2\pi \left(k\in \mathbb{Z}\right)$

$x=-\frac{\pi }{3}+k\pi \left(k\in \mathbb{Z}\right)$

$S=\left\{\frac{\pi }{24}+k\frac{\pi }{2},\frac{7\pi }{24}+k\frac{\pi }{2},k\in \mathbb{Z}\right\}$

$S=\left\{\frac{\pi }{24}+k\pi ,\frac{7\pi }{24}+k\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{\frac{\pi }{24}+k2\pi ,\frac{7\pi }{24}+k2\pi ,k\in \mathbb{Z}\right\}$

$S=\left\{\frac{\pi }{24}+k\frac{\pi }{3},\frac{7\pi }{24}+k\frac{\pi }{3},k\in \mathbb{Z}\right\}$

$[\begin{array}{c}x=k2\pi \\ x=\frac{3\pi }{2}+k2\pi \end{array},k\in \mathbb{Z}$

$[\begin{array}{c}x=k\pi \\ x=\frac{3\pi }{2}+k\pi \end{array},k\in \mathbb{Z}$

$x=\frac{3\pi }{2}+k2\pi ,k\in \mathbb{Z}$

Vô nghiệm

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