Top 5 đề thi Đánh giá năng lực trường ĐHQG Hà Nội có đáp án (Đề 2)

Ấn Độ

Trung Quốc

Thổ Nhĩ Kỳ

Mỹ

-8

-2

2

8

$x=\frac{11}{2}$

$x=5$

$x=\frac{9}{2}$

$x=6$

$\left(x,y\right)\in \left\{\left(2;3\right),\left(4;-9\right)\right\}$

$\left(x,y\right)\in \left\{\left(2;3\right),\left(-4;-9\right)\right\}$

$\left(x,y\right)\in \left\{\left(2;-3\right),\left(-4;-9\right)\right\}$

$\left(x,y\right)\in \left\{\left(2;3\right),\left(4;9\right)\right\}$

$-1+2i$

$-\frac{1}{2}+2i$

$2-i$

$2-\frac{1}{2}i$

$3x+y-7=0$

$x+4y-z-7=0$

$3x+y-14=0$

$x+4y+z-7=0$

$$\left(-2;7;-5\right)$$.

$\left(2;7;-5\right)$.

$\left(2;-7;5\right)$.

$\left(-2;-7;-5\right)$.

$-1$

1

$-3$

0

3

5

2

4

15580000 đồng

18500000 đồng

15850000 đồng

15050000 đồng

$F\left(0\right)=5\ln 2$

$F\left(0\right)=1+\ln 2$

$F\left(0\right)=\ln 2$

$F\left(0\right)=1+5\ln 2$

$m\ge -4$

$m\ge 1$

$m\ge 2$

$m>-5$

10 (m)

6 (m)

12 (m)

8 (m)

420

410

400

390

$x\ge 3$

$1\le x\le 3$

$1<x\le 3$

$x\le 3$

$\frac{8\pi }{3}$

$\frac{10\pi }{3}$

$\frac{16\pi }{3}$

$\frac{2\pi }{3}$

6

7

5

8

(−2;−1)

(−2;−2)

(2;−2)

(2;−1)

$x-2y-2=0$

$x+y-2=0$

$x-y+2=0$

$x-y-2=0$

$\frac{1}{77}$

$\frac{38}{77}$

$\frac{338}{77}$

$\frac{380}{77}$

$m=0$ và $m=1$

$m=4$ và $m=-6$

$m=2$

$m=6$

$2x-z+2=0$

$2x-z=0$

$2x+z=0$

$2x+y-z=0$

$\frac{3a}{2}$

$3a$

$2\sqrt{2}a$

$2a$

$30\pi \left(c{m}^3\right)$

$72\pi \left(c{m}^3\right)$

$48\pi \left(c{m}^3\right)$

$54\pi \left(c{m}^3\right)$

$\frac{a^3\sqrt{3}}{2}$

$a^3\sqrt{6}$

$2\sqrt{3}{a}^3$

$\frac{a^3\sqrt{3}}{3}$

$\frac{12}{5}a$

$\frac{28}{5}a$

$\frac{16}{5}a$

$\frac{24}{5}a$

$I=\left(\frac{29}{3};-\frac{26}{3};-\frac{7}{3}\right)$

$I=\left(\frac{29}{3};\frac{26}{3};-\frac{7}{3}\right)$

$I=\left(\frac{-29}{3};\frac{26}{3};\frac{7}{3}\right)$

$I=\left(-\frac{11}{3};\frac{14}{3};\frac{13}{3}\right)$

$\overrightarrow{u}=\left(0;1;-3\right)$

$\overrightarrow{u}=\left(0;1;3\right)$

$\overrightarrow{u}=\left(2;1;-3\right)$

$\overrightarrow{u}=\left(2;0;0\right)$

12

3

9

6

$\sqrt{17}$

$\sqrt{17+4\sqrt{6}}$

$\sqrt{17+8\sqrt{3}}$

$\sqrt{17+6\sqrt{2}}$

7

8

5

6

5

6

7

8

-8

-24

24

8

$\frac{4}{63}$

$\frac{1}{63}$

$\frac{2}{63}$

$\frac{8}{63}$

$\frac{2\sqrt{2}}{3}$

$\frac{9\sqrt{2}}{32}$

$\frac{16\sqrt{2}}{81}$

$\frac{125\sqrt{2}}{324}$