Top 10 đề thi Đánh giá năng lực ĐHQG Hà Nội năm 2023 - 2024 có đáp án (Đề 2)

Lê Quý Đôn - Hà Đông

Phan Đình Phùng

Chu Văn An

Phạm Hồng Thái

32 m/s

22 m/s

27 m/s

28 m/s

$x=\frac{5}{2}$

$x=\frac{3}{2}$

$x=3$

$$x=1$$

1

2

3

4

$S=\frac{25}{2}$.

$S=5\sqrt{2}$

$S=6$

$S=12$

$x-2y+z+3=0$

$x+2y+3z=0$

$x-2y+z=0$

$x-2y+z-8=0$

$\left(1;0;2020\right)$

$\left(0;6;2020\right)$

$\left(1;6;0\right)$

$\left(1;0;0\right)$

$x=2$

$x=1$

$x=-2$

$x=-1$

6π

2π

3π

5π

408.242 cây.

407.231 cây.

407.232 cây.

408.422 cây.

$F\left(2\right)=\ln \frac{7}{3}$

$F\left(2\right)=-\frac{1}{2}\ln 3$

$F\left(2\right)=\frac{1}{2}\ln \frac{7}{3}$

$F\left(2\right)=\ln 21$

0

Vô số

4

3

$S=95,7\left(m\right)$

$S=96,25\left(m\right)$

$S=94\left(m\right)$

$S=87,5\left(m\right)$

11 (năm).

10 (năm).

8 (năm).

9 (năm).

$\left(0;4\right]$

$\left(0;2\right]$

$\left[2;4\right]$

$\left[1;4\right]$

5

3

4

$\frac{5}{2}$

4

6

2

5

$z=\frac{2}{5}+\frac{4}{5}i$

$z=\frac{1}{2}+\frac{1}{2}i$

$z=\frac{4}{5}+\frac{2}{5}i$

$z=1+\frac{1}{2}i$

$I\left(2;-3\right),R=\sqrt{2}$

$I\left(2;-3\right),R=2$

$I\left(-2;3\right),R=\sqrt{2}$

$I\left(-2;3\right),R=2$

$\frac{1}{20}$

$\frac{81}{20}$

$\frac{121}{20}$

$\frac{441}{20}$

$\alpha =k\pi$

$\alpha =\frac{\pi }{4}+k\pi$

$\alpha =\frac{\pi }{2}+k2\pi$

$\alpha =\frac{\pi }{3}+k\pi$

$2x+5y+3z-9=0$

$2x+y-3z-7=0$

$2x+y-z-5=0$

$x+2y-z-6=0$

$V=\frac{\pi a^2\sqrt{3}}{3}.$

$V=\frac{\pi a^2\sqrt{3}}{6}.$

$V=\frac{\pi a^2\sqrt{3}}{2}.$

$V=\frac{\pi a^2\sqrt{6}}{6}.$

$\frac{1}{\sqrt{3}}$

1

2

$\sqrt{3}$

$\frac{a^3\sqrt{61}}{27}$

$\frac{a^3\sqrt{11}}{9}$

$\frac{2a^3\sqrt{11}}{27}$

$\frac{2a^3\sqrt{11}}{9}$

2

3

$\frac{3}{2}$

$\frac{3}{2}$

$\frac{3\sqrt{2}}{2}$

$\frac{3\sqrt{3}}{2}$

$\frac{5}{2}$

$\Delta :\{\begin{array}{c}x=0\\ y=-3t\\ z=-t\end{array}$

$\Delta :\{\begin{array}{c}x=t\\ y=-3t\\ z=t\end{array}$

$\Delta :\{\begin{array}{c}x=t\\ y=-3t\\ z=-t\end{array}$

$\Delta :\{\begin{array}{c}x=0\\ y=-3t\\ z=t\end{array}$

2.

5.

4.

3.

14

12

−14

−12

3

1

2

4

$m>\frac{9}{2}$

$-\frac{1}{2}\le m\le \frac{9}{2}$

$-\frac{1}{2}<m<\frac{9}{2}$

$m\ge \frac{9}{2}$

$I=\frac{14}{3}$

$I=\frac{28}{3}$

$I=\frac{4}{3}$

$I=2$

$\frac{27}{52}$

$\frac{11}{60}$

$\frac{7}{15}$

$\frac{9}{14}$

$$h=2a;k=\frac{1}{3}$$

$h=a;k=\frac{1}{6}$

$h=2a;k=\frac{1}{8}$

$h=a;k=\frac{1}{4}$